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JavaScript: How to dynamically get the name of the method inside the method in a class?

I would like to get the name of the method inside the method in a class and throw an error when one argument is passed to the method. For example, if the name of the instance is instance_of_cookie and the name of the method is (for simplicity) the_method, then passing one argument to that method should throw an error like "instance_of_cookie.the_method" expected two arguments or simply "the_method" expected two arguments.

I can get the name of the function inside the function using arguments.calle.name. But that doesn't seem to work inside class methods and throws the following error:

VM10:4 Uncaught TypeError: 'caller', 'callee', and 'arguments' properties may not be accessed on strict mode functions or the arguments objects for calls to them
    at Cookie.the_method (<anonymous>:4:28)
    at eval (eval at the_method (:4:28), <anonymous>:1:32)
    at Cookie.the_method (<anonymous>:4:28)
    at <anonymous>:13:32

I came across a post which mentioned this.constructor.name but that gives me the name of the class.

class Cookie {
  the_method(x, y) {
    if (y == undefined) {
      return `'${this.constructor.name}' expects two arguments; one was given`;
    } else {
        return "Everything's OK"
    }
  }
}

let instance_of_cookie = new Cookie();

console.log(instance_of_cookie.the_method(8))

Is there any way I can get the name of the method inside the method in a class?

(Note: I can hard-code the name of the method, but for some reasons, I don't want to do that.)

Via Active questions tagged javascript - Stack Overflow https://ift.tt/rvyiqQR

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