Python program to add the squares of numbers in list which have been entered by while-loop

I'm writing a program which should produce an output of something like this:

`Enter an integer (or Q to quit): 1
Enter an integer (or Q to quit): 2
Enter an integer (or Q to quit): 3
Enter an integer (or Q to quit): Q
(1 x 1) + (2 x 2) + (3 x 3) = 14`

So far, I've gotten the display of the equation right, but I can't seem to figure out how to actually get the total of the equation. Currently, the total displays 18 instead of the expected 14.

Here's my code so far:

`int_list = [] # initiate list 

while True:
  user_input = input("Enter an integer (or Q to quit): ") # get user input
  if user_input == "Q": # break loop if user enters Q
    break
  integer = int(user_input) # convert user_input to an integer to add to list
  int_list.append(integer) # add the integers entered to the list

for i in range(0, len(int_list)):
  template = ("({0} x {1})".format(int_list[i], int_list[i]))
  if i == len(int_list)-1:
    trailing = " = "
  else:
    trailing = " + "
  print(template, end="")
  print(trailing, end="")

for i in range(0, len(int_list)):
  x = (int_list[i]*int_list[i])

add = (x+x)
print(add)`

Any help would be greatly appreciated :))

source https://stackoverflow.com/questions/67766673/python-program-to-add-the-squares-of-numbers-in-list-which-have-been-entered-by