Skip to main content

Raise exception as e in if statement

I have come up with some code to send a file's exceptions as an email, and update a .txt log file. This method works for the following example:

from send_mail import send_error_email
from datetime import datetime
import logging

logging.basicConfig(filename='log.txt', level=logging.DEBUG, format='%(asctime)s %(levelname)s %(name)s %(message)s')
logger=logging.getLogger(__name__)

now = datetime.now()
date = now.strftime("%m/%d/%Y")
time = now.strftime("%H:%M:%S")

try:
    a = 2 + 'seven'
except Exception as e:
    print(e)
    send_error_email(exception=e, message="Can't add string and int")
    logging.exception('Oh no! Error on {} at {} Here is the traceback info:'.format(date, time))

However, the functions I want to apply it to have a lot of if/else syntax where exceptions are raised in the if or else block. Here are two examples:

def is_empty(test_df):
    if(test_df.empty):
        raise Exception("The sheet: {} is empty".format(sheet_name))
    else:
        pass
    for col in test_df.columns:
        miss = test_df[col].isnull().sum()
        if miss>0:
            raise Exception("{} has {} missing value(s)".format(col,miss))
    return None

or

def column_validation(sheet_name, input_file, expected_columns, input_columns, months):
    if len(expected_columns) == len(input_columns):
        for i in range(len(input_columns)):
            if input_columns[i] != expected_columns[i]:
                if sheet_name == "G2 30yr":
                    if input_columns[i][:3] in months:
                        continue
                elif sheet_name != "G2 30yr":
                    if input_columns[i] in months:
                        continue
                else:
                    raise Exception("The {} sheet of file: {}'s columns are not in expected format.".format(sheet_name, input_file))
    else:
        raise Exception("Number of columns in file: {}, {} sheet are not as expected".format(input_file, sheet_name))
    return None

I'm not sure how to employ the emailing and log function with exceptions that are raised outside of try/except blocks where I can access the Exception attributes using except Exception as e:. The below else will send the email notification but will not correctly update the log file.

else:
    send_error_email(exception=e, message="Can't add string and int")
    logging.error('Oh no! Error on {} at {} Here is the traceback info:'.format(date, time), stack_info = True)


source https://stackoverflow.com/questions/72721493/raise-exception-as-e-in-if-statement

Comments

Popular posts from this blog

Why is my reports service not connecting?

I am trying to pull some data from a Postgres database using Node.js and node-postures but I can't figure out why my service isn't connecting. my routes/index.js file: const express = require('express'); const router = express.Router(); const ordersCountController = require('../controllers/ordersCountController'); const ordersController = require('../controllers/ordersController'); const weeklyReportsController = require('../controllers/weeklyReportsController'); router.get('/orders_count', ordersCountController); router.get('/orders', ordersController); router.get('/weekly_reports', weeklyReportsController); module.exports = router; My controllers/weeklyReportsController.js file: const weeklyReportsService = require('../services/weeklyReportsService'); const weeklyReportsController = async (req, res) => { try { const data = await weeklyReportsService; res.json({data}) console...

How to show number of registered users in Laravel based on usertype?

i'm trying to display data from the database in the admin dashboard i used this: <?php use Illuminate\Support\Facades\DB; $users = DB::table('users')->count(); echo $users; ?> and i have successfully get the correct data from the database but what if i want to display a specific data for example in this user table there is "usertype" that specify if the user is normal user or admin i want to user the same code above but to display a specific usertype i tried this: <?php use Illuminate\Support\Facades\DB; $users = DB::table('users')->count()->WHERE usertype =admin; echo $users; ?> but it didn't work, what am i doing wrong? source https://stackoverflow.com/questions/68199726/how-to-show-number-of-registered-users-in-laravel-based-on-usertype

ValueError: X has 10 features, but LinearRegression is expecting 1 features as input

So, I am trying to predict the model but its throwing error like it has 10 features but it expacts only 1. So I am confused can anyone help me with it? more importantly its not working for me when my friend runs it. It works perfectly fine dose anyone know the reason about it? cv = KFold(n_splits = 10) all_loss = [] for i in range(9): # 1st for loop over polynomial orders poly_order = i X_train = make_polynomial(x, poly_order) loss_at_order = [] # initiate a set to collect loss for CV for train_index, test_index in cv.split(X_train): print('TRAIN:', train_index, 'TEST:', test_index) X_train_cv, X_test_cv = X_train[train_index], X_test[test_index] t_train_cv, t_test_cv = t[train_index], t[test_index] reg.fit(X_train_cv, t_train_cv) loss_at_order.append(np.mean((t_test_cv - reg.predict(X_test_cv))**2)) # collect loss at fold all_loss.append(np.mean(loss_at_order)) # collect loss at order plt.plot(np.log(al...