Python | Create a Dictionary with Values as expressions without evaluating or treating it as string

I need to create a dynamic synthetic Pandas DF in Python and am using Faker and Random functions to create the same. To do so, I am creating a dictionary as a source to build pandas df where some columns will have static values whereas some column's values are generated through some expressions or Faker objects based on user input.\

for eg:

if user wants to create synthetic dataframe of size 5 with 2 columns, the user provides two inputs as arguments:

col1 = 1
col2 = tuple('1', '2')

so the dictionary should ideally be constructed as:

dict1 = {
        'col1': 1,
        'col2': fake.random_element(elements=('1','2'))
     }

And the Dataframe can be constructed by running the expressions within the dictionary in a loop, as:

from faker import Faker  
import pandas as pd

fake = Faker()  

def generate_fake_data(numRows, inputDict):
    output = [
                 inputDict for x in range(num)
            ]
    
    return output

num_records = 5
df_sythetic = pd.DataFrame(generate_fake_data(num_records, dict1))

The problem is that if I try to create the dictionary without letting it evaluate the expression for col2 beforehand, it binds the value as string like:

dict1 = {
        'col1': 1,
        'col2': 'fake.random_element(elements=('1','2'))'
     }

How can I create the dictionary without evaluating the expression columns and also not treating them as string ?

source https://stackoverflow.com/questions/76408258/python-create-a-dictionary-with-values-as-expressions-without-evaluating-or-tr