Skip to main content

SVG arg fadeout/gradient effect

I'm trying to create doughnut visualization using d3 with fadeout/gradient effect for each arc like this: enter image description here

I've tried to add 'filter: drop-shadow(0 0 10px color)' but it doesn't give me this effect, also, it spread on both sides.

So I moved to use two pies

  1. Outer solid color
  2. Inner with (hopefully) the fade out effect

I know in gradient I can make solid, then fade out but since I don't have a clear path to success, I split to two pies

I've tried to use both linearGradient & radialGradient on the second pie which seems like a step in a good direction, but the gradient effect changes as the arcs angles are different:

enter image description here

For the simplicity, currently I created a gradient filter for just one color as I'm not sure this is the solution for my problem...

I've added a snippet to help the helpers :)

const colors = ['red','green','purple','blue','orange','teal']
const data = [10,12,33,112,22,4];
const pie = d3.pie().padAngle(0.03);
const arcs = pie(data);

const svg = d3.select('body')
  .append('svg');
 
const svgDefs = svg.append('defs');

const mainGradient = svgDefs.append('radialGradient')
                .attr('id', 'mainGradient');

            mainGradient.append('stop')
                .attr('stop-color', 'red')
                .attr('offset', '10%');

            mainGradient.append('stop')
                .attr('stop-color', 'pink')
                .attr('offset', '90%');



d3.select('body')
  .style('position', 'relative')
  .append('svg')
  .style('position', 'absolute')
  .style('z-index', 10)
  .attr('width', 600)
  .attr('height', 600)
  .append("g")
  .attr("transform", "translate(100,100)")
  .selectAll('path')
  .data(arcs)
  .enter()
  .append('path')
  .attr('d', (a,b,c) => d3.arc()({...a, innerRadius: 96, outerRadius: 100}))
  .style('fill', (d, index) => colors[index])

 svg.style('position', 'absolute')
    .attr('width', 600)
    .attr('height', 600)
  .append("g")
    .attr("transform", "translate(100,100)")
    .selectAll('path')
    .data(arcs)
    .enter()
    .append('path')
      .transition()
      .attr('d', (a,b,c) => d3.arc()({...a, innerRadius: 0, outerRadius: 96}))
      .style('fill', 'url(#mainGradient)')
    
<html>
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/5.14.2/d3.min.js"></script>
<body>
</body>
</html>
Via Active questions tagged javascript - Stack Overflow https://ift.tt/t9AZyWC

Comments

Popular posts from this blog

Confusion between commands.Bot and discord.Client | Which one should I use?

Whenever you look at YouTube tutorials or code from this website there is a real variation. Some developers use client = discord.Client(intents=intents) while the others use bot = commands.Bot(command_prefix="something", intents=intents) . Now I know slightly about the difference but I get errors from different places from my code when I use either of them and its confusing. Especially since there has a few changes over the years in discord.py it is hard to find the real difference. I tried sticking to discord.Client then I found that there are more features in commands.Bot . Then I found errors when using commands.Bot . An example of this is: When I try to use commands.Bot client = commands.Bot(command_prefix=">",intents=intents) async def load(): for filename in os.listdir("./Cogs"): if filename.endswith(".py"): client.load_extension(f"Cogs.{filename[:-3]}") The above doesnt giveany response from my Cogs ...

How to show number of registered users in Laravel based on usertype?

i'm trying to display data from the database in the admin dashboard i used this: <?php use Illuminate\Support\Facades\DB; $users = DB::table('users')->count(); echo $users; ?> and i have successfully get the correct data from the database but what if i want to display a specific data for example in this user table there is "usertype" that specify if the user is normal user or admin i want to user the same code above but to display a specific usertype i tried this: <?php use Illuminate\Support\Facades\DB; $users = DB::table('users')->count()->WHERE usertype =admin; echo $users; ?> but it didn't work, what am i doing wrong? source https://stackoverflow.com/questions/68199726/how-to-show-number-of-registered-users-in-laravel-based-on-usertype

Where and how is this Laravel kernel constructor called? [closed]

Where and how is this Laravel kernel constructor called? public fucntion __construct(Application $app, $Router $roouter) { } I have read the documentation and some online tutorial but I can find any clear explanation. I am learning Laravel and I am wondering where does this kernel constructor receives its arguments from. "POSTMOTERM" CLARIFICATION: Here is more clarity.I have checked the boostrap/app.php and it is only used for boostrapping the interfaces into the container class. What is not clear to me is where and how the Kernel class is instatiated and the arguments passed to the object calling the constructor.Something similar to; obj = new kernel(arg1,arg2) or, is the framework using some magic functions somewhere? Special gratitude to those who burn their eyeballs and brain cells on this trivia before it goes into a full blown menopause alias "MARKED AS DUPLICATE". To some of the itchy-finger keyboard warriors, a.k.a The mods,because I believe in th...