Python Fastest (minimum execution time) approach

I am looking for the fastest, minimum execution time approach to get all the numbers below a "n" number given by the user that are multi-perfect. A number "X" is said to be multi-perfect if the sum of divisors is equal to "X" or "X" multiplied by a int between 2 to 11. Something like this:

sum_div = X --> Multi-perfect number
sum_div = X * k (int between 2 to 11) --> Multi-perfect number

The algorithm that i have currently is this:

def multiperfect(n):
    list=[1]
    for X in range(2, n + 1):
        div = []
        for i in range(1, X):
            if X % i == 0:
                div.append(i)

        sum_div = sum(div)
        if sum_div == X:
            list.append(X)
        else:
            for k in range(2, 11):
                if (k * X == sum_div):
                    list.append(X)

    return list

As you can see this algorithm has 2 iterative structures that make it very very slow O(n^2), i am looking to improve that, any suggestion or advice?

source https://stackoverflow.com/questions/76087605/python-fastest-minimum-execution-time-approach

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