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how can I end the program based on the user's input?

I am trying to make a calculator using functions, but I am really not sure what am I doing wrong here. When the user types n/N the program does not end but continues from the else statement in operation_outcome() function. Seems the next_example() function works fine when the user wants another example, but I am not sure either if the code is written proper way here

def enter_number(num, error):
    notEntered = True
    while notEntered:
        try:
            num = float(input(num))
            notEntered = False

        except ValueError:
            print(error)

        else:
            return num


def operation_outcome(first_num, second_num, choice, error):
    notEntered = True
    while notEntered:
        print("1. addition")
        print("2. subtraction")
        print("3. multiplication")
        print("4. division")

        try:
            choice = int(input(choice))
            if choice >= 1 and choice <= 4:
                if choice == 1:
                    print("the answer is", first_num + second_num)

            elif choice == 2:
                print("the answer is", first_num - second_num)

            elif choice == 3:
                print("the answer is", first_num * second_num)

            elif choice == 4:
                 try:
                    print("the answer is", first_num / second_num)
                 except ZeroDivisionError:
                     print("you cant divide by zero")

            next_example("do you want another example? y/n: ")

        except ValueError:
            print(error)

        else:
            print(error)
            operation_outcome(first_num, second_num, "enter a choice: ", "enter the right value!"
        )

            

def next_example(answer):
    notEntered = True
    while notEntered:
        answer = input(answer)

        if answer == "y" or answer == "Y":
            first_num = enter_number("enter 1. number: ", "enter the right value!")
            second_num = enter_number("enter 2. number: ", "enter the right value!")
            operation_outcome(  first_num, second_num, "enter a choice: ", "enter the right value!"
        )
          

        elif answer == "n" or answer == "N":
            print("end of the program.")
            return False

        else:
            print("enter the right value!")


first_num = enter_number("enter 1. number: ", "enter the right value!")
second_num = enter_number("enter 2. number: ", "enter the right value!")
operation_outcome(first_num, second_num, "enter a choice: ", "enter the right value!")


source https://stackoverflow.com/questions/76607123/how-can-i-end-the-program-based-on-the-users-input

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