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Uncaught TypeError: mysqli_error(): Argument #1 ($mysql) must be of type mysqli, string given in C:\xamppCópia\cadastrar.php:76 Stack trace: #0

Estou tendo esse erro ao inserir dados na tabela Fatal error: Uncaught TypeError: mysqli_error(): Argument #1 ($mysql) must be of type mysqli, string given in C:\xampp\htdocs\devy\DAVID - Cópia\adm\cadastrar.php:76 Stack trace: #0 C:\xampp\htdocs\devy\DAVID - Cópia\adm\cadastrar.php(76): mysqli_error('INSERT INTO pri...') #1 {main} thrown in C:\xampp\htdocs\devy\DAVID - Cópia\adm\cadastrar.php on line 76

            $inserir = "INSERT INTO prisioneiro (`nome`, `apelido`, `datanascimento`, `sexo`, `identidade`, `contacto`,`endereco`, `provincia`, `cidade`, `sela`, `dataentrada`, `datasaidada`,`tipo_prisao`, `acusacao`, `arquivo`)
            VALUES ( '$nome', '$apelido', '$datanascimento', '$sexo', '$identidade','$contacto', '$endereco', '$provincia', '$cidade','$sela', current_timestamp(), '$datasaida','$tipo_prisao', '$acusacao', '$novo_nome')";
                
                if(mysqli_query($conn, $inserir) ){
                    // $msg = "<div class=\"alert alert-success\" role=\"alert\">Registo efectuado com sucesso</div>";
                    // header("Location:admregistar.php?msg=$msg");
                     echo"SUCESSO";
                    
                }   
                else{
                //  $msg = "<div class=\"alert alert-danger\" role=\"alert\">Falhou o registo. Tente novamente!</div>";
                //  header ("Location:admregistar.php?msg=$msg");
                    
                echo mysqli_error($inserir);
                echo"error".$inserir."<br>".$conn->error;
                 $conexao->close();
    
                }   
}

?>

A linha 76 é essa echo mysqli_error($inserir);

Diz que o erro está na linha 76 mais eu não consigo identificar o que há de erra nessa linha



source https://stackoverflow.com/questions/69396538/uncaught-typeerror-mysqli-error-argument-1-mysql-must-be-of-type-mysqli
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