Show/hide button based on if condition React

I have a button called download, it is a component. The functionality is written in a container.

I want the button to be hidden as default, unless the "(i === number)" condition is true in the download function.

However, it is tricky, since this condition will only be validated when I click "download". I am not sure how do I validate this logic beforehand to determine if the button needs to be displayed or not.

Can you please help? What would be the most convenient way in this case

My code basically looks like this -

container:

download = async () => {
 const data = await this.props.client
     .query({
         query: numberQuery,
         fetchPolicy: "no-cache",
     })
 // retrive data from number qeury ....
 const contentData = data.data.content;

 // retrieve and format numbers
 const numbers = this.getNumbers(contentData);

 // call get number and get the individual number here
 const number = await this.getNumber();

 numbers.forEach((i) => {
    // this is to check if numbers contain the number from getNumber(), if 
    // number matches number in numbers
    if (i === number) {
         // call functions, start downloading
    };
  });
 };

render() {
  return (
   <Download 
     onStartDownload={() => this.download()}
   />
 );
};

component:

class Download extends Component {
 state = {
   startDownload: false,
 };

 startDownload = () => {
   this.props.onStartDownload();
 };

 render() {
   return (
     <Fragment>
       <Button
         id="download"
         onClick={this.startDownload}
       >
         Download
       </Button>
     </Fragment>
    );
   };
 };

Thank you!

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