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How to match more than 2 number in a row?

I have 2 data frames that I would like to match more than 2 numbers that match in the row I'm looking up.

import pandas as pd 

cols = ['Num1','Num2','Num3','Num4','Num5','Num6']
df1 = pd.DataFrame([[2,4,6,8,9,10]], columns=cols)

df2 = pd.DataFrame([[1,1,2,4,5,6,8],
               [2,5,6,20,22,23,34],
               [3,8,12,13,34,45,46],
               [4,9,10,14,29,32,33],
               [5,1,22,13,23,33,35],
               [6,1,6,7,8,9,10],
               [7,0,2,3,5,6,8]], 
               columns = ['Id','Num1','Num2','Num3','Num4','Num5','Num6'])

I have this code that matches but i would like to enhance by matching more than 2 numbers in the row.

 # convert the values in the first dataframe to a list
   vals_to_find = df1.iloc[0].tolist()

 # Print the values to find
   print("Vals to find:", vals_to_find)

 # Create an empty list to hold the matching IDs
   matching_ids = []

# iterate through the big dataframe 
  for index, row in df2.iterrows():

  rowlist = row.tolist()       # convert the row to a list

# keep the id for later, and extract the other values for evaluation
  id = rowlist[0]
  vals = rowlist[1:]

# count the number of values in one list against another list
counter = sum(elem in vals_to_find for elem in vals)

# If the number of matches is greater than 2, then grab the ID
if counter > 2:
    matching_ids.append({'ID': id})

# Print the matching IDs 
  print('Matching IDS:', matching_ids)

I would like my results to be something like that..

df3 = pd.DataFrame([[6,1,6,7,8,9,10],
               [7,0,2,3,5,6,8]], 
               columns = ['Id', 'Num1','Num2','Num3','Num4','Num5','Num6'])


source https://stackoverflow.com/questions/74867149/how-to-match-more-than-2-number-in-a-row
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