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Get the list of names which satisfy the condition in dictionary from given list

I have a dictionary in which there are three conditions startwith, contains and endwith given below,

dict1 = {'startwith':"Raja, Bina", 'contains':"Tata", "endwith":""}

If user give value in dictionary with comma that means OR i.e "Raja, Bina" = Raja or Bina

now I have a list of name given below

list_of_names = ["Raja Molli Jira", "Bina Tata Birla", "Fira Kiya Too"]

now with above dictionary and list I have to find the name from list which satisfy the conditions given in dictionary, from above example result should be like (need result in list)

required_list = ["Raja Molli Jira", "Bina Tata Birla"]

the name in required_list satisfy the condition given in dictionary which are startwith and contains.

Example 2

if dict1 and list_of_names are :

dict1 = {'startwith':"", 'contains':"Tata, Gola", "endwith":"Too"}
list_of_names = ["Raja Molli Jira", "Bina Tata Birla", "Fira Kiya Too"]

the required_list list will be :

required_list = ["Bina Tata Birla", "Fira Kiya Too"]

the name in required_list satisfy the condition given in dictionary which are contains and endwith

Currently using code

I am able to handle problem if user give single value (without comma) with below code

dict1 = {'startwith':"Raja,Bina", 'contains':"Tata", "endwith":""}
list_of_names = ["Raja Molli Jira", "Bina Tata Birla", 'Fira Kiya Too']
required_list = []
fileopp  = list(dict1.values())

for i in list_of_files:
   #startswith
   if  ((fileopp[0] != "") and (fileopp[1] == "") and (fileopp[2] == "")):
        if i.startswith(fileopp[0]):
               listfilename.append(i)
   #containswith
  elif ((fileopp[0] == "") and (fileopp[1] != '') and (fileopp[2] == "")):
        if i.__contains__(fileopp[1]):
               listfilename.append(i)
   #endiswith
   elif ((fileopp[0] == "") and (fileopp[1] == '') and (fileopp[2] != "")):
        if i.endswith(fileopp[2]):
            listfilename.append(i)
   #startswith and contains with
   elif ((fileopp[0] != "") and (fileopp[1] != "") and (fileopp[2] == "")):
        if (i.startswith(fileopp[0])) and i.__contains__(fileopp[1]):
            listfilename.append(i)
   #startswith and endswith
   elif ((fileopp[0] != "") and (fileopp[1] == "") and (fileopp[2] != "")):
        if (i.startswith(fileopp[0])) and i.endswith(fileopp[2]):
            listfilename.append(i)
   #containswith and endswith
   elif ((fileopp[0] == "") and (fileopp[1] != "") and (fileopp[2] != "")):
        if (i.__contains__(fileopp[1])) and i.endswith(fileopp[2]):
            listfilename.append(i)

Question

If user give Value with comma (Raja,Bina) then above code fails to give result.

Giving the conditions and required result what I want,

First

dict1 = {'startwith':"Fira", 'contains':"", "endwith":"Birla"}
list_of_names = ["Raja Molli Jira", "Bina Tata Birla", "Fira Kiya Too"]

required_list = ["Bina Tata Birla", "Fira Kiya Too"]

Second

dict1 = {'startwith':"Fira, Raja", 'contains':"", "endwith":""}
list_of_names = ["Raja Molli Jira", "Bina Tata Birla", "Fira Kiya Too"]

required_list = ["Raja Molli Jira", "Fira Kiya Too"]


source https://stackoverflow.com/questions/75127926/get-the-list-of-names-which-satisfy-the-condition-in-dictionary-from-given-list
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