Skip to main content

Populating an input type text field, according to previous dropdown selection in form using php & ajax

As the title says, I am trying to populate a text input according to a dynamic drop down list, but I can not get it to work. Below is my form:

<div class="form-group">
    <label for="mealcategorytype"" class="col-12 col-form-label">Meal Category </label>
        <div class="col-12">
           <select class="form-control " name="categ_type" id="mealcategorytype">
            <option  value='' disabled selected>Select Meal Category...</option>
             <?php
               require_once '_db.php';                                         
               $stmt= $db->prepare("SELECT * FROM `rate_type_categories`");                                        
               $stmt->execute();
               $values=$stmt->fetchAll();  
                                                                                               
               foreach($values as $value)
               {                                                
                if($value['rate_type_category_id']==$rowCatRatePlan['rate_type_category_id'])
                {
                 echo 
                '<option selected value="'.$value['rate_type_category_id'].'">'.$value['rate_type_category_name'].'</option>';
                }
                else
                {
                 echo '<option value="'.$value['rate_type_category_id'].'">'.$value['rate_type_category_name'].'</option>';
                }
              }  ?>                 
          </select>
        </div>
   </div>


   <div class="form-group ">
     <label for="example-date-input" class="col-12 col-form-label">Rate Plan Charge Percentage</label>
    <div class="col-12">
     <input class="form-control"  id="ratepercent" name='rate_percentage' type="text" value=''>
    </div>
   </div>

By selecting the required rate type category (you will see it as meal category also in my code ), I want to populate the the next field ( Rate Plan Charge Percentage ) with the selected category's Rate Plan Charge Percentage from the database.

rate type category table in link:

enter image description here

this is the script that I tried using :

$(document).ready(function(){  
      $('#mealcategorytype').change(function(){  
           var mealCategory_id = $(this).val();  
           alert($this);
           $.ajax({  
                url:"match_meal_category_to_rate_plan.php",  
                method:"POST",  
                data:{mealCategoryID:mealCategory_id},  
                success:function(data){  
                     $('#ratepercent').val(data);  
                     //$('#ratedocdesc').html(data);  
                     
                }  
           });  
      });  
 });  

and the code in the page where the ajax request will be sent :

$output='';
$getMealCategContent="SELECT * FROM rate_type_categories WHERE rate_type_category_id  = '".$_POST['mealCategoryID']."'  ";
echo $getMealCategContent;
$resultMealCategContent=mysqli_query($conn,$getMealCategContent);

while($rowCategContent=mysqli_fetch_array($resultMealCategContent))
{
  $output.='        
  <input class="form-control"  id="ratepercent" name="rate_percentage" type="text" value="'.$rowCategContent["rate_category_charge_percentage"].'"> ';
}                                 
echo $output;

What am I doing wrong?



source https://stackoverflow.com/questions/68967133/populating-an-input-type-text-field-according-to-previous-dropdown-selection-in

Comments

Popular posts from this blog

How to show number of registered users in Laravel based on usertype?

i'm trying to display data from the database in the admin dashboard i used this: <?php use Illuminate\Support\Facades\DB; $users = DB::table('users')->count(); echo $users; ?> and i have successfully get the correct data from the database but what if i want to display a specific data for example in this user table there is "usertype" that specify if the user is normal user or admin i want to user the same code above but to display a specific usertype i tried this: <?php use Illuminate\Support\Facades\DB; $users = DB::table('users')->count()->WHERE usertype =admin; echo $users; ?> but it didn't work, what am i doing wrong? source https://stackoverflow.com/questions/68199726/how-to-show-number-of-registered-users-in-laravel-based-on-usertype

Why is my reports service not connecting?

I am trying to pull some data from a Postgres database using Node.js and node-postures but I can't figure out why my service isn't connecting. my routes/index.js file: const express = require('express'); const router = express.Router(); const ordersCountController = require('../controllers/ordersCountController'); const ordersController = require('../controllers/ordersController'); const weeklyReportsController = require('../controllers/weeklyReportsController'); router.get('/orders_count', ordersCountController); router.get('/orders', ordersController); router.get('/weekly_reports', weeklyReportsController); module.exports = router; My controllers/weeklyReportsController.js file: const weeklyReportsService = require('../services/weeklyReportsService'); const weeklyReportsController = async (req, res) => { try { const data = await weeklyReportsService; res.json({data}) console...

How to split a rinex file if I need 24 hours data

Trying to divide rinex file using the command gfzrnx but getting this error. While doing that getting this error msg 'gfzrnx' is not recognized as an internal or external command Trying to split rinex file using the command gfzrnx. also install'gfzrnx'. my doubt is I need to run this program in 'gfzrnx' or in 'cmdprompt'. I am expecting a rinex file with 24 hrs or 1 day data.I Have 48 hrs data in RINEX format. Please help me to solve this issue. source https://stackoverflow.com/questions/75385367/how-to-split-a-rinex-file-if-i-need-24-hours-data