Skip to main content

Problem with showing correct delivery date

I have a website which shows the delivery date when you search product

P.S as an example, I use today's order which was created 30.08.2021 14:12

Delivery date on the search result page show this code:

       if(time_to_exe == 7)
    {
var orderDateTime = moment();
// Get Monday (first day) of this week and add 3 days (to get to Thursday) and set the time to 11:59am
var cutOffDate = moment().startOf('week').add(3,'days').set({'hour': 11, 'minute': 59, 'second': 59});
// Initialize delivery date from order date
var deliveryDate = orderDateTime.clone();
if (orderDateTime.isSameOrBefore(cutOffDate)) {
    deliveryDate = deliveryDate.add(1,'week').startOf('week'); // Monday next week
} else {
    deliveryDate = deliveryDate.add(2,'week').startOf('week'); // Monday the week after next
}
    
    if (deliveryDate) {
  time_to_exe = deliveryDate.format("D. MMMM");
      
    } else {
      time_to_exe = time_to_exe + "d";
    }
    }

As the order was created in the time between Monday 30.08.2021 00:00 and Thursday 02.09.2021 11:59:59 the delivery date is 06.09.2021 which is correct

Then I have an Order page where clients can see all created orders and there is a delivery date as well. And there, the delivery date shows this code:

$item_time is defined as an order created date (in this case 30.08.2021 14:12)

if($item_t2_time_to_exe == 7)
{
    
    $paymentDate = strftime("%d/%m/%y %H:%M:%S",$item_time);
//echo $paymentDate; // echos today! 
$contractDateBegin = strftime("%d/%m/%y %H:%M:%S",strtotime('monday this week', $item_time));
$contractDateEnd = strftime("%d/%m/%y 11:59:59", strtotime('thursday this week', $item_time));
    
if (($paymentDate >= $contractDateBegin) && ($paymentDate <= $contractDateEnd)){
     $nextMonday = strftime("%e.%B", strtotime('next monday',$item_time));
}else{
    $nextMonday = strftime("%e.%B", strtotime('second monday',$item_time));  
}
   if($nextMonday) 
   {
       $delivery = $nextMonday;
   }
   else
   {
       
       $delivery = "error";
   }
    
}

And there it should be the same delivery date 06.09.2021 as it is on the search result page, but for now, the code executes else and return me 'second monday' and show 13.09.2021 as a delivery date. I can't understand why it is so, any suggestions?

Via Active questions tagged javascript - Stack Overflow https://ift.tt/2FdjaAW

Labels

Labels:

Comments

Post a Comment

Popular posts from this blog

Why is my reports service not connecting?

I am trying to pull some data from a Postgres database using Node.js and node-postures but I can't figure out why my service isn't connecting. my routes/index.js file: const express = require('express'); const router = express.Router(); const ordersCountController = require('../controllers/ordersCountController'); const ordersController = require('../controllers/ordersController'); const weeklyReportsController = require('../controllers/weeklyReportsController'); router.get('/orders_count', ordersCountController); router.get('/orders', ordersController); router.get('/weekly_reports', weeklyReportsController); module.exports = router; My controllers/weeklyReportsController.js file: const weeklyReportsService = require('../services/weeklyReportsService'); const weeklyReportsController = async (req, res) => { try { const data = await weeklyReportsService; res.json({data}) console...
Post a Comment
Read more

How to show number of registered users in Laravel based on usertype?

i'm trying to display data from the database in the admin dashboard i used this: <?php use Illuminate\Support\Facades\DB; $users = DB::table('users')->count(); echo $users; ?> and i have successfully get the correct data from the database but what if i want to display a specific data for example in this user table there is "usertype" that specify if the user is normal user or admin i want to user the same code above but to display a specific usertype i tried this: <?php use Illuminate\Support\Facades\DB; $users = DB::table('users')->count()->WHERE usertype =admin; echo $users; ?> but it didn't work, what am i doing wrong? source https://stackoverflow.com/questions/68199726/how-to-show-number-of-registered-users-in-laravel-based-on-usertype
Post a Comment
Read more

ValueError: X has 10 features, but LinearRegression is expecting 1 features as input

So, I am trying to predict the model but its throwing error like it has 10 features but it expacts only 1. So I am confused can anyone help me with it? more importantly its not working for me when my friend runs it. It works perfectly fine dose anyone know the reason about it? cv = KFold(n_splits = 10) all_loss = [] for i in range(9): # 1st for loop over polynomial orders poly_order = i X_train = make_polynomial(x, poly_order) loss_at_order = [] # initiate a set to collect loss for CV for train_index, test_index in cv.split(X_train): print('TRAIN:', train_index, 'TEST:', test_index) X_train_cv, X_test_cv = X_train[train_index], X_test[test_index] t_train_cv, t_test_cv = t[train_index], t[test_index] reg.fit(X_train_cv, t_train_cv) loss_at_order.append(np.mean((t_test_cv - reg.predict(X_test_cv))**2)) # collect loss at fold all_loss.append(np.mean(loss_at_order)) # collect loss at order plt.plot(np.log(al...
Post a Comment
Read more