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How to display default image when user's photo is null or empty in php? [duplicate]

How can I show the default image that I assigned if the user's image path does not exist or when the user did not insert any image there?

<? php 
...

else if (isset($_POST['update_btn'])){
  
$target = "icons/".basename($_FILES['image_path']['name']);


$id = $_POST['idNum'];
$fn = $_POST['firstName'];
$ln = $_POST['lastName'];
$em = $_POST['email'];
$pw = $_POST['password'];
$cn = $_POST['contactNum'];
$ad = $_POST['address'];
$ct = $_POST['city'];

$im=$_FILES['image_path']['name'];
$old_image = $_POST['stud_image_old'];

if($im !='')
{
  $update_filename = $_FILES['image_path']['name'];
}
else{
  $update_filename = $old_image;
}

if(file_exists("icons/" .$_FILES['image_path']['name']))
{
    $filename = $_FILES['image_path']['name'];
    $_SESSION['status'] = "Image already exists.".$filename;
    header('location: updateUser.php');
}  
 
    $result = $mysqli->query("UPDATE tb_usersreg SET firstName='$fn', lastName='$ln', email='$em', password='$pw', image_path='$update_filename', contactNum='$cn', address='$ad', city='$ct' WHERE idNum='$id'") or die($mysqli->error);
    $result_run = mysqli_query($mysqli, $result);
      
      if(result_run){
        if($_FILES['image_path']['name'] !=''){
            move_uploaded_file($_FILES['image_path']['tmp_name'], "icons/".$_FILES['image_path']['name']);
            unlink("icons/".$old_image);
        }
            $_SESSION['status'] = "Data updated succesfully.";
        }
        else{
          $_SESSION['status'] = "Data not updated.";
        }

if($result)
{
  echo '<div class="success">';  
  echo "<h3>Updated succesfully!</h3>";
  echo '</div>';
}
else{
  echo '<div class="success">'; 
  echo "<h3>Unsuccesful.</h3>";
  echo '</div>';
}

header('location: registeredIndiv.php');
}

?>


source https://stackoverflow.com/questions/69752397/how-to-display-default-image-when-users-photo-is-null-or-empty-in-php
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