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Change the argument of a function that is inside another function

This are my tasks:

This is my tasks

As you can see, they all have "same" logic. So I wanted use function like this ->

const task71=(x)=>Math.tan(2*x+x*x);
const main=(x,dX,xEnd)=>{
  while(x<=xEnd)
  {
    task71(x); //this part I wanna change, so it will work for task72,task73...
    x+=dX;
    console.log(`Y=${task71(x)}\nX=${x}`);
  }
}

This works only for task71(x),but I have task72(x),task73(x),etc. What do I need to change in main(x,dx,xEnd) function to make it work for another functions? I tried use task71(x) as argument, but in this way the function only works with the initial value of x.

Perhaps this question is stupid, sorry, I recently started learning programming.

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