I am trying to write an efficient algorithm that will find the number of jumps it will take for a pawn to exit an array. Lets say we are given an array, for each element in the array if array[k] = n then array[k] is equal to array[k + n];
For example, we have this array [2,3,-1,1,3].
Initially the pawn is at array[0], on first jump it moves from array[0] to array[2] because 0 + array[0] is equal to 2. on the second jump, the pawn moves from A[2] to A[1] because 2 + A[2] = 1; on the third jump, the pawn moves from A[1] to A[4] because 1 + A[1] = 4; on the fourth jump, the pawn jumps out of the array. It returns 4 for this test case.
If the pawn cant jump out of the array we return -1;
Below is the algorithm I wrote for this problem and it works for a few test cases but fails large test cases. How can I make this algorithm more efficient.
function jumpOut(A) {
let start = 0;
let end = A.length - 1
let pawn = 0;
while (start < end){
pawn= start + A[start]
start++;
}
if(pawn === end){
return pawn
}
return -1;
}
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